Question

if 2 is a root of both the equations ax2+ax+3=0 and x2​+x+b=0 then find ab.

Answer 1

Solution is attached below in image

Answer 2

Step-by-step explanation:

ax^2+ax+3=0

a(-2)^2+a(-2)+3=0

a(4)-2a= -3

4a-2a= -3

a= -3/2

a= -1.5

now b

x^2-x+b=0

(-2)^2+(-2)+b=0

4-2+b=0

2+b=0

b=2

a= -1.5

b=2

I hope it will help you

Thank you