Write the electronic configuration of:- (1) Al3+ (2) F- (3) Ca (4) Ne (5) P
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Al3+=(13-3)=10 =2,8
F-=(9+1)=10 =2,8
Ca =(20)= 2,8,8,2
Ne=(10) = 2,8
P=(15)=2,8,5
F-=(9+1)=10 =2,8
Ca =(20)= 2,8,8,2
Ne=(10) = 2,8
P=(15)=2,8,5
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