if 2 is a root of equation X square + bx + 12 equal to zero find the value of B
Answers
Answered by
40
Hey!!!
Good Morning
_______________
we have
=> x² + bx + 12 = 0
Here 2 is to root
=> (2)² + 2x + 12 = 0
=> 2x = - 16
=> x = - 8 <<<<<<<<< Answer
________________
Hope this helps ✌️
Happy Ganesh Chaturthi
Good Morning
_______________
we have
=> x² + bx + 12 = 0
Here 2 is to root
=> (2)² + 2x + 12 = 0
=> 2x = - 16
=> x = - 8 <<<<<<<<< Answer
________________
Hope this helps ✌️
Happy Ganesh Chaturthi
Answered by
40
Hey dear friend
Given-:
2 is a root of eq.[ X²+bX+12]=0
To Find-:
Value of B=?
Solution-:
=>As 2 is root of equation.
=>So, Substituting X=2 in equation
=>We get,
=>2²+2b+12=0
=>4+2b+12=0
=>16+2b=0
=>2b= -16
=>b= -8
So, the value of 'b'= -8.
Be PERFECTIONIST
hope it helps you mark me as brainliest and follow me
Given-:
2 is a root of eq.[ X²+bX+12]=0
To Find-:
Value of B=?
Solution-:
=>As 2 is root of equation.
=>So, Substituting X=2 in equation
=>We get,
=>2²+2b+12=0
=>4+2b+12=0
=>16+2b=0
=>2b= -16
=>b= -8
So, the value of 'b'= -8.
Be PERFECTIONIST
hope it helps you mark me as brainliest and follow me
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