Question

if 2 is a root of the equation x2+kx+12=0 find the value of b .hence find the other root

Answer 1

the value oj the k is -8

Answer 2

I think this is the answer of your question.

x2 + kx +12=0.

2 is a root of the equation.

Then, 4+2k+12=0.

Then, 2k+16=0.

So, 2k= -16.

Therefore, k= -8.

x2+kx+q=0.

x2-8k+q=0.

Equal roots, so b2 =4ac.

64=4*1*q

q=16.