Math, asked by brainlyshacker58, 7 months ago


If 2 is added to the numerator of a fraction, it reduces to 1/2 and if 1 is subtracted from the denominator, it reduces to 1/3 . Find the fraction.

Answers

Answered by Anonymous
27

Qᴜᴇsᴛɪᴏɴ :-

If 2 is added to the numerator of a fraction, it reduces to 1/2 and if 1 is subtracted from the denominator, it reduces to 1/3 . Find the fraction.

Gɪᴠᴇɴ :-

If we add 2 to the numerator of fraction it reduces 1/2

If 1 is subtracted from the denominator it reduces 1/3

Tᴏ Fɪɴᴅ :-

Fraction

Sᴏʟᴜᴛɪᴏɴ :-

Let the fraction be x

According to 1st condition, if we add 2 to the numerator it reduces 1/2

⟾ x + 2/y = 1/2

⟾ (x + 2)2 = y

⟾ y = 2x + 4 __________①

According to 2nd condition

If we subtract 1 from the fraction it reduces 1/3

⟾ x/y - 1 = 1/3

⟾ 3x = y - 1

⟾ x = y-1/3__________②

Now, substituting value of y from ①st equation in ②nd equation

⟾ x = (2x + 4)-1 / 3

⟾ 3x = 2x + 3

⟾ 3x - 2x = 3

⟾ x = 3

Putting value of x in ①st equation

⟾ y = 2 × 3 + 4

⟾ y = 6 + 4

⟾ y = 10

⛬ Fraction = 3/10

Answered by Anonymous
27

Given

If 2 is added to the numerator of a fraction, it reduces to 1/2 and if 1 is subtracted from the denominator, it reduces to 1/3

To find

Find the required fraction

Solution

Let the required fraction be x/y

If 2 is added to the numerator of the fraction, it reduces to 1/2

  • x + 2/y = 1/2 --- (i)

1 is subtracted from the denominator, it reduces to 1/3

  • x/y - 1 = 1/3 ---- (ii)

From (i)

➨ x + 2/y = 1/2

➨ y = 2(x + 2)

➨ y = 2x + 4

By substitution method

Substitute the value of y in eqⁿ (ii)

➨ x/y - 1 = 1/3

➨ x/2x + 4 - 1 = 1/3

➨ x/2x + 3 = 1/3

➨ 3x = 2x + 3

➨ 3x - 2x = 3

➨ x = 3

Putting the value of x in y = 2x + 4

➨ y = 2x + 4

➨ y = 2 × 3 + 4

➨ y = 6 + 4

➨ y = 10

**Hence, the required fraction = x/y

= 3/10

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