Question

If 2 is the zero of the polynomial kx square +(3k-2)x + k then find the value of k

Answer 1

u mean the equation is
(Kx)sq + ( 3k - 2)x + k and we have to find k

so u are saying x = 2 right
then we have to just replace the value of x by 2 and get the answer
( k x 0)sq + 3kx - 2x + k = 0
0 + 3kx - 2x + k = 0
6k - 4 + k = 0 ( x =2)
- 4 = - 7k
k = 4/7

Answer 2

P(2)=k(2)²+(3k-2)2+k
=4k+6k-4+k
=5k+6k-4
=11k-4=0
11k =4
Therefore k=4/11