if 2 is the zero of the polynomial p(x) =x2 -kx+6 then k?
Answers
Answered by
1
Putting the value 2 in the polynomial we get
P(2)= 2^2-k×2+6=9
=> 4-2k+6=0
2-2k=0
-2k= -2
K= -2+2
K= 0
Hope it helps u!!
P(2)= 2^2-k×2+6=9
=> 4-2k+6=0
2-2k=0
-2k= -2
K= -2+2
K= 0
Hope it helps u!!
Answered by
1
as 2is zero of the polynomial
therefore ,
2 * 2-k * 2+6
4-k * 8
4-8k=0
-8k=-4
k=-5+8
k=3
therefore ,
2 * 2-k * 2+6
4-k * 8
4-8k=0
-8k=-4
k=-5+8
k=3
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