Question

If 2 is the zero of the polynomial, px2+(p-2) x+2, what is the value of p?????????

Answer 1

Answer:

Step-by-step explanation:

2 is a zero of px^2 + (p - 2)x + 2, then 4p + 2(p - 2) + 2 = 0 then 6p - 2 = 0, then 6p = 2, then p = 1 / 3.

Answer 2

Step-by-step explanation:

Px2+(p-2)x+2

As 2 is zero of this polynomial

Therefore

P(4)=p(2)2 +(p-2)2+2

=4p+(p-2)4

4p+4p-8=0

8p-8=0

8p=8

P=8/8

P=1 ans..