Question

If -2 is the zero of x^2-kx-k then find the value of k

Answer 1

Given that -2 is the zero of the given equation,

So,

x = -2 

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x^2 -  kx - k = 0 

(-2)^2 -k(-2) - k= 0 

4 + 2k - k = 0 

4 + k = 0 

k = -4





i hope this will help you


-by ABHAY

Answer 2

Heya
here's your answer....
$p(x) = {x}^{2} - kx - k \\ p( - 2) = { (- 2)}^{2} - ( - 2k) - k = 0 \\ = 4 + 2k - k = 0 \\ = 4 + k = 0 \\ k = 0 - 4 \\ k = - 4$
hope it helps...✌✌
PLS MARK IT AS BRAINLIEST✌

Answer 3

Heya
here's your answer....
$p(x) = {x}^{2} - kx - k \\ p( - 2) = { (- 2)}^{2} - ( - 2k) - k = 0 \\ = 4 + 2k - k = 0 \\ = 4 + k = 0 \\ k = 0 - 4 \\ k = - 4$
hope it helps...✌✌
PLS MARK IT AS BRAINLIEST✌