Question

If 2 is zero of equation 2x^2 -3k=2, then the value of k is

Answer 1

Step-by-step explanation:

Hiii

put 2 in place of x

f(2)=0

2(2)^2-3k=2

2×4-2=3k

8-2=3k

6=3k

k=2

Answer 2

$\huge\underline\mathbb{\red Q\pink{U}\purple{ES} \blue{T} \orange{IO}\green{N :}}$

If 2 is zero of equation 2x^2 -3k=2, then the value of k is...?

$\huge\underline\mathbb{\red S\pink{O}\purple{LU} \blue{T} \orange{IO}\green{N :}}$

★ Given that,

2 is zero of the equation " p(x) = 2x² - 3k = 2 ".

p(x) = 2

Substitute the value of x in the p(x)

$\sf\:⟹ 2(2)² - 3k = 2$

$\sf\:⟹ 8 - 3k = 2$

$\sf\:⟹ 8 - 2 = 3k$

$\sf\:⟹ 3k = 6$

$\sf\:⟹ k = \frac{6}{3} = 2$

$\underline{\boxed{\bf{\purple{∴ Hence, \: the \: value \: of \: k \: is \:2}}}}} </p><p>$