Question

if (2,k)is one solution of equation x+y+2=0,then what is the value of k?​

Answer 1

$\textbf{Given:}$

$\textsf{(2,k) is one solution of x+y+2=0}$

$\textbf{To find:}$

$\textsf{The value of k}$

$\textbf{Solution:}$

$\textsf{Since (2,k) is solution of x+y+2=0,}$

$\textsf{(2,k) will satisfy x+y+2=0}$

$\implies\mathsf{2+k+2=0}$

$\implies\mathsf{k+4=0}$

$\implies\boxed{\mathsf{k=-4}}$

$\underline{\textbf{Answer:}}$

$\textsf{The value of k is -4}$

$\textbf{Find more:}$

If X=2p+1 and y=p-1 is a solution of the linear equation 2x-3y+5=0, then find the value of p.​

https://brainly.in/question/18146156

Answer 2

Given : Equation is = x + y + 2 = 0 ………(1)

(2, k) is one solution of the above given equation .

To find: The value of k.

Solution:

It is given that (2,k) is a solution of the equation then it must satisfy the given equation.

Here, x = 2 and y = k

Now put these values in equation (1), we get:

x + y + 2 = 0

2 + k + 2 = 0

4 + k = 0

k = 0 - 4

k = - 4

Hence, the value of k is - 4.

Learn more:

Find the value of k for which pair of linear equations 3x + 2y = –5 and x - ky = 2 has a unique solution.

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For what value of p the pair of linear equations (p+ 2)x - (2p + 1)y = 3(2p -1) and 2x- 3y = 7 has a unique solution.

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