If 2 log x + 3 log y - 2 = 0, prove that xsquare ycube = 100
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Answer:
Substitute y = 100 in eqn 2
log x + logy = 5
log x + log (100) = 5
log x + 2 = 5. log x = 3
log has a base of 10 x given as
x = 10 pow(3)
x = 1000.
I hope it will help you!!!!!!!!!!!!!!!!
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