Math, asked by siddhartha21soumya, 8 months ago

if 2^m+n÷2^m-n=16 and 3^p÷3^n=a^1/5 then (a^2m+n-p)÷(a^m-2n+2p)^-1

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Answered by studs
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if 2^m+n÷2^m-n=16 and 3^p÷3^n=a^1/5 then (a^2m+n-p)÷(a^m-2n+2p)^-1

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