Question

If 2 moles of h2 and 2 moles of i2 are taken in 10l conatainer . Calculate the equilibrium constant of the reaction

Answer 1

Let at equilibrium, [H2] = [I2] = x

                              2HI (g)H2 (g) + I2 (g)

Initial conc.            2/10 M                   0           0

At equilibrium        0.2 -2x                   x            x  

 

                           0.125 = x / (0.2-2x)

                            x = 0.025-0.25x

                            x = 0.025 /1.25    

                            x=0.02

    Therefore, the equilibrium conc. of H2, I2 and HI are

                   [H2] =0.02M

                  [I2] =0.02M

                  [HI] =0.2-0.02 =0.18M

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