Question

If 2 opposite side of llgram are (63-3x) and (4x-7) find all angles of llgram

Answer 1

[tex]63 - 3x = 4x - 7 \\ 63 + 7 = 4x + 3x \\ 70 = 7x \\ x = \frac{70}{7} = 10 \\ two \: angles \: of \: parallellogram = 63 - 3x \\ 63 - 3 \times 10 = 63 - 30 = 33 \: cm \\ 4x - 7 = 4 \times 10 - 7 = 40 - 7 = 33cm

Answer 2

opposite angles of parellog
ram are equal so
63-3x=4x-7
-3x-4x= -7-63
-7x= -70
x= -70/-7
x=10
63- 3x= 63-3×10
=63-30
=33
4x-7= 4×10-7
=40-7
=33
now , the the other two equal opposite angles be y
33 + y + 33+ y= 180 degree
66 + 2y = 180
2y = 180 -66
2y = 114
y=114/2
y =57 degree