Question

If 2 positive integer p and q are written as p=a2b3
And q= a3b ; a, b are prime number then verify
LCM (p, q) x HCF (p, q)=pq

In simple all steps and 3 and 2 are representing square and cube

Answer 1

hope this may helps you

Answer 2

As we know,
p=a^2b^3
q=a^3b
LCM(LEAST COMMON ✖) =a^2b^3 and a^3b
Therefore, LCM=a^3b^3 ----1

and, HCF(HIGHEST COMMON ✖)


HCF=a^2b -----2
from 1 and 2
we got,
a^5b^4
Hence proved