Question

if 2 sin 2 tita =root 3 the value of tita is​

Answer 1

Solution:

$\rm{2 \: sin2 \theta = \sqrt{3} }$

Dividing by 2 on both sides,

$\longrightarrow \: \sf{sin2 \theta = \dfrac{ \sqrt{3} }{2} }$

√3/2 can also be written as sin 60°

$\longrightarrow \: \sf{sin \: 2 \theta = sin \: 60^{ \circ} }$

Taking sin inverse on both sides,

$\longrightarrow \: \sf{2 \theta = {60}^{ \circ} }$

For finding the value of θ, divide both sides by 2.

$\longrightarrow \: \sf{ \theta = \dfrac{60^{ \circ} }{2} }$

$\therefore \boxed{ \bf{ \theta = {30}^{ \circ} }}$

Answer 2

Step-by-step explanation:

Given,

$\: \: \: \: \: \: \: \sf \:2 \: sin \: 2 \theta = \sqrt{3} \\ \sf \implies \: sin \: 2 \theta = \frac{ \sqrt{3} }{2} \\ \sf \implies \: 2 \theta = {sin}^{ - 1} ( \frac{ \sqrt{3} }{2} ) \\ \sf \implies \: 2 \theta = {60}^{ \circ} \\ \sf \implies \: \theta = \frac{60}{2} \\ \sf \therefore \: \theta = {30}^{ \circ}$