if 2 sin 2thita = root2 then find the value of cos thita
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2sin 2∅=\sqrt{2}
then 2(sin∅)=\sqrt{2}
sin∅=\sqrt{2}/2=1/\sqrt{2}
sin∅=1/cos∅
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1/cos∅=1/\sqrt{2}
therefore, cos∅=\sqrt{2}
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