if 2 sin (A+B) = √3 and tan B=1, find Sin2B
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Step-by-step explanation:
2 sin (A+B) = √3
sin (A+B) = √3/2
sin (A+B) = sin60°
A + B = 60° ...................1
tanB = 1
tanB = tan45°
B = 45°
sin2B = sin2x45°
= sin90°
= 1
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