if 2 sin square theta - cos square theta equal to 2 , then find the value of theta
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Step-by-step explanation:
2sin²theta- cos²theta =2
=> 2 (1-cos²theta) - cos²theta = 2
=> 2-3cos²theta = 2
=> -3cos²theta = 0
=> cos²theta = 0
=> cos theta = 0
=> theta = (2n+1) π/2 , n€ I
or theta = π/2, 3π/2, 5π/2........
hope this helps you
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