Question

if 2 sin theeta - 4cos theeta = 0, find tan²theeta + 1 / sec theeta​

Answer 1

Answer:

Solution

We have,

3 sin 0 + 4cos = 5

. (1)

On squaring both sides, we get

(3 sin 0 + 4cos0)² = 5²

9sin²0+16cos²0 + 24 sin cos

= 25

9 (1 − cos²0) + 16 (1 - sin²0) + 12×

2 sin Ꮎ cos Ꮎ

: 25

99cos²0 +16 - 16sin²0 + 12 x

2 sin cos = 25

259cos²016sin²0 + 12 × 2 sin 0 cos 0 = 25 9cos²0 + 16sin²0 12 x 2 sin 0 cos 0 = 0

(3 cos 0 - 4sin0)² = 0

3 cos - 4sin 0

Hence, the value is 0.

Answer 2

Answer:

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Step-by-step explanation:

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