if 2 sin theta = root 3 then find cot theta + cosec theta ?
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2sin theta = √3
sin theta = √3/2
=> theta = 60°
to find: cot theta + cosec theta
put the value of theta
cot 60° + cosec 60°
= 1/√3 + 2/√3
= 3/√3
=√3
hope it will help you........
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