Question

If 2 sin²x = 3-3cosx . Find sec x​

Answer 1

Step-by-step explanation:

sin ^2 x + cos ^2 x = 1

2 sin ^ 2 x = 2 -2cos ^ 2 x = 3 - 3 cos x

2 - 2 cos^ 2 x = 3 - 3cos x

3cos x - 2 cos ^2 x - 1 =0

2x square - 3x + 1 = 0

where x = cos x and (multiplied -1 for eqn)

solving the equation we get the roots x= 1,1/2

there fore 1) cos x = 1

sec x = 1/cos x

sec x = 1

in the same way x = 1 /2 sec x = 2

don't think that cos x = x x values are same