Question

if 2 soaps of radius r cm is combine and make a new soap bubble then find the radius of new soap bubble?​

Answer 1

Since 2 soap bubbles made a bigger soap bubble ;

Thus

• vol.(bigger soap bubble) = vol.(2×small soap bubble)

Let the radius of small soap bubble be r .

Let the radius of big soap bubble be r'.

Since their volumes are equal

Therefore;

$2 \times \frac{4}{3} \pi {r}^{3} = \frac{4}{3} \pi {r'}^{3} \\ 2 \times {r}^{3} = {r'}^{3}$

Thus

r'³ = 2r³

r' = ³√(2r³)

r' = r(³√2)

#answerwithquality

#BAL