if 2 tan =3 find the value of 4sin-3cos/2sin+6cos
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2tan=3
tan=3/2
tan thetha=opposite side/adjacent side
therefore 3 is the opposite side (BC) and AB is 2.
Draw a right angled triangle ABC..right angled at B ,such that BC is the base,AB is the altitude,AC is the hypotenuse.
Usng pythogoras theorem...
AC2=AB2+BC2
AC2=9+4=13
AC=ROOT13
sin=oppo.side/hypotenuse=3/root13
cos=2/root13
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