If 2 TANA = 3TAN B, prove that Tan (A-B)=sin2B/5-Cos2B
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tan(A−B)
=tanA−tanB1+tanAtanB
=tanB2+3tan2B
=tanBcos2B2cos2B+3tan2Bcos2B
=sin2B4+2sin2B
=sin2B5−cos2B
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