if 2 tanA=cotB then show that cos(A-B)=3cos(A+B)
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2 tan A = cot B
2sinA/cos A=cos B/sinB
2sinAsinB=cosAcosB
Cos(A-B)=cosAcosB+sinAsinB
=2sinAsinB+sinAsinB
=3sinAsinB
=3(2sinAsinB-sinAsinB)
3(cosAcosB-sinAsinB)
3cos(A+B)
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