if 2 to the power of x+1=3to the power of 1-x then find the value of x
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Step-by-step explanation:
(2)^(x+1)=(3)^(1-x)
apply log on both sides
(x+1)log2=(1-x)log3
x(log2+log3)=(log3-log2)
therefore x={log(3/2)/log6}
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