Question

if 2 vertices of a equilateral triangle are (0,0) (3,√3) find the third vertex

Answer 1

the formula is (x1+x2)+-(y1-y2)/2 and (y1+y2)-+(x1-x2)/2
ok
it will help you

Answer 2

Let 3 vertices of equilateral triangle be A,B, and C.
d (A, B )=
$\sqrt{(3 - 0) { }^{2} } + \sqrt{ (\sqrt{3 - 0} }) {}^{2}$
=
$\sqrt{9 + 3}$
=
$\sqrt{12}$
=
$\sqrt{4 \times 3}$
=
$2 \sqrt{3}$
Third vertice is
$2 \sqrt{3}$