Question

if (2^x) - (2^x-1) =4 then what is the value of x^x​

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Answer 1

Answer:

Answer is 27

Explanation:

${2}^{x} - {2}^{x - 1} = 4 \\ \\ {2}^{x} - {2}^{x - 1} = 4 \\ \\ {2}^{x} - \frac{ {2}^{x} }{2} = 4 \\ \\ {2}^{x} (1 - \frac{1}{2} ) = 4 \\ \\ \frac{ {2}^{x} }{2} = 4 \\ \\ {2}^{x} = 8 \\ \\ {2}^{x} = {2}^{3} \\ \\ x = 3$

Now here we get x = 3

To find : x^x

${x}^{x} = {3}^{3} \\ \\ = 27$

$\rule{200}{2}$

◼ Rules used :-

${x}^{a} \times {x}^{b} = {x}^{a + b} \\ \\ {x}^{n} = {x}^{m} then \\ \\ n = m$

Answer 2

Answer:

27

Explanation:

Given,

${2}^{x} - ( {2}^{x - 1} ) = 4$

Now,

$by \: taking \: {2}^{x - 1} \\ \\ {2}^{x - 1} ( 2 - 1)= 4 \\ \\ {2}^{x - 1} (1) = 4 \\ \\ {2}^{x - 1} = 4 \\ \\ {2}^{x - 1} = {2}^{2} \\ \\ x - 1 = 2 \\ \\ x = 2 + 1 \\ \\ x = 3$

Here, x = 3

Then,

x^x = 3³ = 27

Hope it helps