If 2^x=3^y=12^z, prove that x = 2yz/y-z
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Heya!!
Given Question is
2^x = 3^y = 12^z
let 2^x = 3^y = 12^z = k
2^x = k , 3^y = k And 12^z = k
2 = k^(1/x) , 3 = k^(1/y) And 12 = k^(1/z)
12 = k^(1/z)
2² × 3 = k^(1/z)
k^(1/2x) × k^(1/y) = k^(1/z)
k^{(1/2x) + (1/y)} = k^(1/z)
Now, Compare powers of k we have!!)
(1/2x) + (1/y) = (1/z)
1/2x = (1/z) - (1/y)
1/2x = (y - z)/zy
2x = zy / (y - z)
x = 2yz/ (y - z): Hence, proved.
Note:-
IF aⁿ = b
Then a = b^(1/n)
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