If 2^x =3^y=6^z ,prove that 1/x+1/y+1/z=0 or z=xy/x+y
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Let 2^x = 3^y = 6^z = k
This means that,
x = log k base 2
y = log k base 3
And,
z = log k base 6
Now,
1/x = 1/log k base 2 = log 2 base k
Similarly,
1/y = log 3 base k
And
1/z = log 6 base k
Now,
1/x + 1/y = log 2 base k + log 3 base k = log 6 base k = 1/z
Hence proved that,
1/x + 1/y = 1/z
Hope this helps you !
This means that,
x = log k base 2
y = log k base 3
And,
z = log k base 6
Now,
1/x = 1/log k base 2 = log 2 base k
Similarly,
1/y = log 3 base k
And
1/z = log 6 base k
Now,
1/x + 1/y = log 2 base k + log 3 base k = log 6 base k = 1/z
Hence proved that,
1/x + 1/y = 1/z
Hope this helps you !
adarshkumar56:
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