Question

If 2^x=3^y=6^-z then 1 upon x + 1 upon y + 1 upon z is equal to :

Answer 1

Answer:

0

Step-by-step explanation:

 Given  

If 2^x=3^y=6^-z then 1 upon x + 1 upon y + 1 upon z is equal to :

ANSWER

 Let 2^x = 3^y = 6 ^-z = P

  Now 2^x = P

  P^1/x = 2

  Similarly P^1/y = 3 and P^-1/z = 6

  P^-1/z = 6

  P^-1/z = 2 x 3

 P^-1/z = P^1/x . P^1/y

 P^-1/z = P^1/x + 1/y (a^m x a^n = a^m + n)

 When bases are same, exponents are equal

         1/z = 1/x + 1/y

  So   1/x + 1/y + 1/z = 0