Question

if 2^x+y=32 and 2^x-y=16 then find value of x​

Answer 1

Step-by-step explanation:

${2}^{x + y} = 32 = {2}^{5} = > x + y = 5$

${2}^{x - y} = 16 = {2}^{4} = > x - y = 4$

Hence add both these equations we get 2x=9 =>x=9/2 or 4.5. Hope it helps you.