if 2011³+3×(2011)² +3(2011)+1=k then k is
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Let (a1,a2,a3,...,a2011) be a permutation ( that is a rearrangement) of the num- bers 1,2,3, ...,2011. Show that there exist two numbers j, k ...
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This is the formula of (a+b)³
Therefore, k= (2011+1)³
k=(2012)³
k=8,144,865,728
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