Question

If cos A=√3/2
and 'A' is acute, then the value of 4 sin²A+ tan²A​

Answer 1

since, cos A = √3/2

so, cosA= cos30 degree.

A= 30 .......

now, 4 sin sq 30 + tan sq 30 = 4× 1/2+ 1/√3= 2√3+1/√3 = or 6+√3/ 3.....

mark my answer as verified.....

Answer 2

Answer:

sin^2A= 1-cos^2A

= 1- 3/4

sinA = 1/2

tanA=sinA/cosA

= √3/2/1/2

=√3

4sin^2A+tan^2A=4( 1/2)^2+(√3)^2

=4(1/4)+3

= 1+3

=4

Mark brainliest plz