Question

If 20g of salt is present in 220g of solution, calculate the concentration of solution

Answer 1

Given - Mass of solute = 20g

To Find - Concentration of solution

Solution -

The given problem can be solved using the below-mentioned method that is as follow:

Let 'm' be the mass of solution, 'M' be the mass of solvent and 'C' be the concentration of the given solution.

As per the given conditions,

Mass of solute (m) = 20g

Mass of solution (m + M) = 220g ..... [as a mass of the (solute + solvent) makes up the mass of the solution] ........(1)

Formula - Concentration of solution = Mass of solute/(Mass of solute + Mass of the solvent) * 100

∴ C = m/(m + M)*100

∴ By putting the given values in the above-mentioned formula. we get,

C = 20/220*100 ..........(from 1)

C = 0.0909

∴ C = 9.09%

Hence, the concentration of the given solution is 9.09%

Answer 2

Answer:

The solution's $W/W\%$ concentration calculated is $9.09\%$.

Explanation:

Given data,

The weight of salt, $W_{salt}$ = $20g$

The weight of the solution, $W_{sol}$ = $220g$

The solution's $W/W\%$ concentration =?

From the formula given below, we can find out the solution's concentration:

• Concentration ( $W/W\%$ ) = $\frac{W_{salt}}{W_{sol}} \times 100$

After putting the given values of the salt's weight and the solution's weight in the equation, we get:

• Concentration ( $W/W\%$ ) = $\frac{20}{220} \times 100$ = $9.09\%$.

Hence, the solution's $W/W\%$ concentration calculated is $9.09\%$.