Find the zeros of the quadratic polynomial 4u²+ 8u.
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Answered by
58
4u² + 8u = 0
4u(u+ 2) = 0
4u= 0, u = 0
u+2= 0, u= -2
4u(u+ 2) = 0
4u= 0, u = 0
u+2= 0, u= -2
Answered by
62
4u²+8u=0
4u(u+2)=0
4u=0
u=0 or
u+2=0
u=-2
u=0 and u=-2 are the zeroes of the given polynomial
4u(u+2)=0
4u=0
u=0 or
u+2=0
u=-2
u=0 and u=-2 are the zeroes of the given polynomial
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