If 21y5 is a multiple of 9,where y is a digit,what is the value of y.?
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The value of 'y' is 1, because the sum of the digits has to be a multiple of 9 if it is divisible by 9. So, 2+1+y+5=8+y. The nearest multiple of 9 to 8 is 9, so 9-8=1.
Thus, y's value is 9. Hope this helps!
Thus, y's value is 9. Hope this helps!
rudraprakashdon:
Right.thnx
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