If 21y5 is a multiple of 9, where y is a digit, what is the value of y?
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If 21y5 is a multiple of 9, where y is a digit, what is the value of y? Solution : For a number to be a multiple of 9, sum of all of its digits should be divisible by 9. So, (8+y) should be divisible by 9 if value of y is 1.
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property
if a number should be divisible by 9 then the sum of the digit must be divisible by 9
according to property
2+1+y+5= multiple of 9
8+y=9(suppose,becausey must be 1 digit)
therefore y=1
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