Question

If 22.0g co2 react with 34g of nh3 to form ammonium carbamate what will be amount of ammonium carbamate

Answer 1

Explanation:

Convert masses given to moles, and use each to calculate the mass of product formed:

CO2:

22.0 g CO2 / 44.0 g/mol X (1 mol carbamate/1 mol CO2) X 78.07 g/mol = 39.0 g ammonium carbamate

NH3:

34 g NH3 / 17 g/mol X (1 mol carbamate / 2 mol NH3) X 78.07 g/mol = 78.1 g ammonium carbamate

From these results, CO2 is the limiting reactant, and the theoretical yield of ammonium carbamate is 39 grams. So, C is the correct answer.