Question

If 220 V potential difference is applied across an electric bulb, a current of 0.45
A flows in the bulb. what must be the power of the bulb?

Answer 1

from P=w/t
and w=vit
so p=vit/t
or p=vi
therefore

P=220×0.45
P=99 watt

Answer 2

Here, P=?

V=220

I=0.45

We know that,

P=VI

=220×0.45

=99 W