if 220V potential difference is applied across an electric bulb, a current of 0.45A flows in the bulb. What must be power of the bulb
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Answered by
3
from P=w/t
and w=vit
so p=vit/t
or p=vi
therefore_
P=220×0.45
P=99 watt
and w=vit
so p=vit/t
or p=vi
therefore_
P=220×0.45
P=99 watt
Answered by
1
P=VxI
=220x0.45=99 watt
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