If (23 – x ) is the mean proportional of ( 28 – x) and (19 – x ) , then
find the value of x.
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(28-x):(23-x)::(23-x):(19-x)
Product of extremes = Product of means
(23-x)^2 = (28-x)(19-x)
x^2+529-46x = x^2-47x+532
x=3
Therefore value of x is 3
Please mark as brainliest answer
Product of extremes = Product of means
(23-x)^2 = (28-x)(19-x)
x^2+529-46x = x^2-47x+532
x=3
Therefore value of x is 3
Please mark as brainliest answer
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