Math, asked by sangrawat008, 1 year ago

if 2352=2x × 3y × 7z , then the value of x + y + z

Answers

Answered by princesspranjal24
13
refer to the attachment for the answer...
Attachments:
Answered by imhkp4u
3

Answer:

x + y + z = 4 + 1 + 2 = 7 [Ans]

Step-by-step explanation:

According to the question in order to find the values of x y z we must know what are the factors of 2352.

The factors of 2352 are:

2352 = (2*2*2*2)*(3*1)*(7*7). = 2^{4} * 3^{1} * 7²

Comparing it with 2352 = 2^{x}  * 3^{y} * 7^{z} we get,

x = 4; y = 1 and z = 2.

∴Therefore the sum of x,y and z will be (4+1+2) equals to 7.

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