Question

If 2400 J of energy is used to heat up a 3kg copper block from 20 Celsius to 22 Celsius, what is the specific heat capacity of copper???!

Answer 1

Answer:

400 $\frac{Joule}{kg~^{o}C }$

Explanation:

Energy = mass × specific heat × ΔT

Specific heat = $\frac{Energy}{mass~*~T_{diff.} }$

S = $\frac{2400}{3~*~2}$ = 400 $\frac{Joule}{kg~^{o}C }$

Answer 2

Answer:

what do I know and by the way thanq u for giving ur points to me