If 24th term of an
a.p. is twice the 10th term, prove that 72th term is twice the 34th term.
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a+23d=2(a+9d)
a+23d=2a+18d
a=5d
now 72th term=a+71d=76d
34th term=a+33d=38d
so 76d=2*38d
it is proved that 72th term is twice the 34th term
a+23d=2a+18d
a=5d
now 72th term=a+71d=76d
34th term=a+33d=38d
so 76d=2*38d
it is proved that 72th term is twice the 34th term
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