If 25% of a certain work is done by a and after that remaining was done by b, the work will be completed in 20 days. if 75% of the work is done by a and the remaining is done by b, the work will be completed in 30 days. if a and b work together, in how many days work will be completed
Answers
Answered by
5
Solution:-
Using the formula : Work = Rate*Time
Time = Work/Rate
Assuming A's rate of work as 'A'
Assuming B's rate of work as 'B'
A does 25 % of the work, so A did 25/100 = 0.25 part of the work.
B does 75 % of the work, so A did 75/100 = 0.75 part of the work.
Days for which A worked + Days for which B worked = Total Days
Work of A/Rate of A + Work of B/Rate of B = Total Days
Situation 1 -
0.25/A + 0.75/B = 20
Multiplying the above by 12, we get.
⇒ 3/A + 9/B = 240 .....................(1)
Situation 2 -
0.75/A + 0.25/B = 30
Multiplying the above by 4, we get.
3/A + 1/B = 120 .......... (2)
Subtracting (2) from (1), we get.
3/A + 9/B = 240
3/A + 1/B = 120
- - -
________________
8/B = 120
________________
⇒ 8/B = 120
⇒ 120B = 8
⇒ B = 8/120
⇒ B = 1/15
Now, Substituting B = 1/15 in (2)
⇒3/A + 1/B = 120
⇒ 3/A + 1÷1/15 = 120
⇒ 3/A + 1*15 = 120
⇒ 3/A + 15 = 120
⇒ 3/A = 120 - 15
⇒ 3/A = 105
⇒ 105A = 3
⇒ A = 3/105
⇒ A = 1/35
Now, combined rate = 1/15 + 1/35
Taking L.C.M. of the denominator and then solving it.
⇒ (7 + 3)/105
⇒ 10/105
Time taken when working together = 105/10
⇒ 21/2
⇒ 10 1/2 days
Hence, if A and B work together, the work will be completed in 10 1/2 days.
Answer.
Using the formula : Work = Rate*Time
Time = Work/Rate
Assuming A's rate of work as 'A'
Assuming B's rate of work as 'B'
A does 25 % of the work, so A did 25/100 = 0.25 part of the work.
B does 75 % of the work, so A did 75/100 = 0.75 part of the work.
Days for which A worked + Days for which B worked = Total Days
Work of A/Rate of A + Work of B/Rate of B = Total Days
Situation 1 -
0.25/A + 0.75/B = 20
Multiplying the above by 12, we get.
⇒ 3/A + 9/B = 240 .....................(1)
Situation 2 -
0.75/A + 0.25/B = 30
Multiplying the above by 4, we get.
3/A + 1/B = 120 .......... (2)
Subtracting (2) from (1), we get.
3/A + 9/B = 240
3/A + 1/B = 120
- - -
________________
8/B = 120
________________
⇒ 8/B = 120
⇒ 120B = 8
⇒ B = 8/120
⇒ B = 1/15
Now, Substituting B = 1/15 in (2)
⇒3/A + 1/B = 120
⇒ 3/A + 1÷1/15 = 120
⇒ 3/A + 1*15 = 120
⇒ 3/A + 15 = 120
⇒ 3/A = 120 - 15
⇒ 3/A = 105
⇒ 105A = 3
⇒ A = 3/105
⇒ A = 1/35
Now, combined rate = 1/15 + 1/35
Taking L.C.M. of the denominator and then solving it.
⇒ (7 + 3)/105
⇒ 10/105
Time taken when working together = 105/10
⇒ 21/2
⇒ 10 1/2 days
Hence, if A and B work together, the work will be completed in 10 1/2 days.
Answer.
Similar questions