Question

If 25ml of a h2so4 solutions reacts with 1.06g of pure na2co3 what is the normality of this solution

Answer 1

We have an equation, N1V1 = N2V2 where N1 and N2 are normalities and V1 and V2 the volumes.

NV= number of equivalents= Given mass/equivalent mass.

Equivalent mass= Molas Mass/n factor.

Here, molar mass of Na2CO3= 106gm.

N factor is 2, thus Equivalent mass is 106/2= 53gm.

Thus number of equivalents = 1.06/53= 0.02=N1V1

V1= 0.025

Thus N1= 0.02/0.025=0.8 N

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