If 27×32=3^x×2^y; find the values of x and y.No spam or will be reported
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y = x^x^x^x^-------infinite
we can write it-----
y = x^y
taking log both side
log y = log (x^y)
log y = y log x
taking differentiation both side with respect to x
d/dx (log y) = d/dx (y log x)
1/y*dy/dx = y* d/dx(logx)+logx*dy/dx
1/y*dy/dx = y / x+logx*dy/dx
dy/dx (1/y - logx) = y/x
Hope it helped you a lot
dy/dx = y^2 / x(1 - y lox)
Answered by
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Answer:
3x
Step-by-step explanation:
If 27 × 32 = 3x × 2y; find the values of x and y.
27 × 32 = 3x × 2y
27 = 3x
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