Math, asked by Anonymous, 1 month ago

If 27×32=3^x×2^y; find the values of x and y.No spam or will be reported​

Answers

Answered by ItzBrainly0
0

y = x^x^x^x^-------infinite

we can write it-----

y = x^y

taking log both side

log y = log (x^y)

log y = y log x

taking differentiation both side with respect to x

d/dx (log y) = d/dx (y log x)

1/y*dy/dx = y* d/dx(logx)+logx*dy/dx

1/y*dy/dx = y / x+logx*dy/dx

dy/dx (1/y - logx) = y/x

Hope it helped you a lot

dy/dx = y^2 / x(1 - y lox)

Answered by ashishnautiyal449
0

Answer:

3x

Step-by-step explanation:

If 27 × 32 = 3x × 2y; find the values of x and y.

27 × 32 = 3x × 2y

27 = 3x

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